久违的ac,真是艰难。第一次提交的竟然是直接判断b字符串是否为a的倒序。

#include<iostream>
#include<stack>
#include<string>
using namespace std;
int main()
{
    int t;
    string a,b;
    while(cin>>t>>a>>b)
    {
        stack<char>s;
        string p;
        int i=0;
        t=a.size();
        while(t--)
        {
            s.push(a[a.size()-t-1]);
            p+="in\n";//cout<<s.top()<<"   "<<b[i];
            while(!s.empty()&&s.top()==b[i])
            {
                //cout<<"i"<<i<<endl;
                s.pop();
                p+="out\n";
                i++;
        //cout<<s.size()<<"!!"<<endl;
            }
        }
        if(s.size()==0)
            cout<<"Yes."<<endl<<p;
        else
            cout<<"No."<<endl;
        cout<<"FINISH"<<endl;
    }
    return 0;
}